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Higher Derivatives

Note that a partial derivative is itself a function of two variables, and so further partial derivatives can be calculated. We write

$\displaystyle {\frac{{\partial}}{{\partial x}}}$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ = $\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$,        $\displaystyle {\frac{{\partial}}{{\partial x}}}$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$ = $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$,        $\displaystyle {\frac{{\partial}}{{\partial y}}}$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ = $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} }}}$,        $\displaystyle {\frac{{\partial}}{{\partial y}}}$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$ = $\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$.

This notation generalises to more than two variables, and to more than two derivatives in the way you would expect. There is a complication that does not occur when dealing with functions of a single variable; there are four derivatives of second order, as follows:

$\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$,        $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$,        $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} }}}$    and    $\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$.

Fortunately, when f has mild restrictions, the order in which the differentiation is done doesn't matter.

Proposition 8.12   Assume that all second order derivatives of f exist and are continuous. Then the mixed second order partial derivatives of f are equal. i.e.

$\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$ = $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} }}}$.

Example 8.13   Suppose that f (x, y) is written in terms of u and v where x  =  u + log v and y  =  u - log v. Show that, with the usual convention,

$\displaystyle {\frac{{\partial^{2}f}}{{\partial u^{2}}}}$ = $\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$ + 2$\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$

and

v2$\displaystyle {\frac{{\partial^{2}f}}{{\partial v^{2}}}}$ = $\displaystyle {\frac{{\partial f}}{{\partial y}}}$ - $\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$ + 2$\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$

You may assume that all second order derivatives of f exist and are continuous.

Solution. Using the chain rule, we have

$\displaystyle {\frac{{\partial f}}{{\partial u}}}$ = $\displaystyle {\frac{{\partial f}}{{\partial x}}}$$\displaystyle {\frac{{\partial x}}{{\partial u}}}$ + $\displaystyle {\frac{{\partial f}}{{\partial y}}}$$\displaystyle {\frac{{\partial y}}{{\partial u}}}$ = $\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{\partial f}}{{\partial y}}}$    and    $\displaystyle {\frac{{\partial f}}{{\partial v}}}$ = $\displaystyle {\frac{{\partial f}}{{\partial x}}}$$\displaystyle {\frac{{\partial x}}{{\partial v}}}$ + $\displaystyle {\frac{{\partial f}}{{\partial y}}}$$\displaystyle {\frac{{\partial y}}{{\partial v}}}$ = $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ - $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$.

Thus using both these and their operator form, we have
$\displaystyle {\frac{{\partial^{2}f}}{{\partial u^{2}}}}$ = $\displaystyle {\frac{{\partial}}{{\partial u}}}$$\displaystyle \left(\vphantom{\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} }\right.$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{\partial f}}{{\partial y}}}$$\displaystyle \left.\vphantom{\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} }\right)$ = $\displaystyle {\frac{{\partial}}{{\partial x}}}$ + $\displaystyle {\frac{{\partial}}{{\partial y}}}$$\displaystyle \left(\vphantom{\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} }\right.$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{\partial f}}{{\partial y}}}$$\displaystyle \left.\vphantom{\frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} }\right)$ = $\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} }}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$,  
whiledifferentiatingwithrespectto$v$, wehave


$\displaystyle {\frac{{\partial^{2}f}}{{\partial v^{2}}}}$

= $\displaystyle {\frac{{\partial}}{{\partial v}}}$$\displaystyle \left(\vphantom{\frac{1 }{ v}\frac{\partial f}{\partial x} -\frac{1}{ v} \frac{\partial f}{\partial y}}\right.$$\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ - $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$$\displaystyle \left.\vphantom{\frac{1 }{ v}\frac{\partial f}{\partial x} -\frac{1}{ v} \frac{\partial f}{\partial y}}\right)$ = - $\displaystyle {\frac{{1 }}{{ v^2}}}$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial}}{{\partial v}}}$$\displaystyle \left(\vphantom{ \frac{\partial f}{\partial x} }\right.$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$$\displaystyle \left.\vphantom{ \frac{\partial f}{\partial x} }\right)$ + $\displaystyle {\frac{{1 }}{{ v^2}}}$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$ - $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial}}{{\partial v}}}$$\displaystyle \left(\vphantom{ \frac{\partial f}{\partial y} }\right.$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$$\displaystyle \left.\vphantom{ \frac{\partial f}{\partial y} }\right)$  
  = - $\displaystyle {\frac{{1 }}{{ v^2}}}$$\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle \left(\vphantom{\frac{1 }{ v}\frac{\partial^{2}f}{\partial x^{2}}...
...}f}{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} } }\right.$$\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$ - $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} }}}$$\displaystyle \left.\vphantom{\frac{1 }{ v}\frac{\partial^{2}f}{\partial x^{2}}...
...}f}{
\partial{\if 11y\else y^{1}\fi}
\partial{\if 11x\else x^{1}\fi} } }\right)$ + $\displaystyle {\frac{{1 }}{{ v^2}}}$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$ - $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle \left(\vphantom{\frac{1 }{ v} \frac{\partial^{2}f}{
\partial{\if ...
...1y\else y^{1}\fi} } -\frac{1}{ v} \frac{\partial^{2}f}{\partial y^{2}} }\right.$$\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$ - $\displaystyle {\frac{{1 }}{{ v}}}$$\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$$\displaystyle \left.\vphantom{\frac{1 }{ v} \frac{\partial^{2}f}{
\partial{\if ...
...1y\else y^{1}\fi} } -\frac{1}{ v} \frac{\partial^{2}f}{\partial y^{2}} }\right)$  
  = $\displaystyle {\frac{{1 }}{{ v^2}}}$$\displaystyle \left(\vphantom{ \frac{\partial f}{\partial y} - \frac{\partial f...
...artial{\if 11y\else y^{1}\fi} } + \frac{\partial^{2}f}{\partial y^{2}} }\right.$$\displaystyle {\frac{{\partial f}}{{\partial y}}}$ - $\displaystyle {\frac{{\partial f}}{{\partial x}}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{\partial x^{2}}}}$ - 2$\displaystyle {\frac{{\partial^{2}f}}{{
\partial{\if 11x\else x^{1}\fi}
\partial{\if 11y\else y^{1}\fi} }}}$ + $\displaystyle {\frac{{\partial^{2}f}}{{\partial y^{2}}}}$$\displaystyle \left.\vphantom{ \frac{\partial f}{\partial y} - \frac{\partial f...
...artial{\if 11y\else y^{1}\fi} } + \frac{\partial^{2}f}{\partial y^{2}} }\right)$.  



next up previous contents index
Next: Solving equations by Substitution Up: Differentiation of Functions of Previous: Partial Differentiation   Contents   Index
Ian Craw 2002-01-07