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Table of Integrals

This is a short table of some standard integrals. The left column is the function and the right column is an indefinite integral for it. You can add in a constant of integration if you want to.

Anything with a logarithm in it is to be treated with caution!




xn          $\displaystyle {\frac{1}{n+1}}$xn + 1          n$ \ne$ - 1
$\displaystyle {\frac{1}{x}}$          ln|x|          see text for problems
$\displaystyle {\frac{1}{ax+b}}$          $\displaystyle {\frac{1}{a}}$ln|ax + b|          as above
$\displaystyle {\frac{x}{ax+b}}$          $\displaystyle {\frac{1}{a^2}}$$\displaystyle \left(\vphantom{ ax+b-b\ln\vert ax+b\vert}\right.$ax + b - b ln|ax + b|$\displaystyle \left.\vphantom{ ax+b-b\ln\vert ax+b\vert}\right)$          as above
$\displaystyle {\frac{1}{a^2 + x^2}}$          $\displaystyle {\frac{1}{a}}$arctan(x/a)         
$\displaystyle {\frac{1}{\sqrt{a^2-x^2}}}$          arcsin(x/a)          0$ \le$x$ \le$a
$\displaystyle {\frac{1}{\sqrt{x^2-a^2}}}$          ln(x + $\displaystyle \sqrt{x^2-a^2}$)          0$ \le$a$ \le$x
$\displaystyle {\frac{1}{\sqrt{x^2+a^2}}}$          ln(x + $\displaystyle \sqrt{x^2+a^2}$)         
sin x          -cos x         
cos x          sin x         
sec2x          tan x         
$\displaystyle \cosec^{2}_{}$x          -cot x         
tan x          -lncos x         
sec x          ln(sec x + tan x)         
$\displaystyle \cosec$x          ln($\displaystyle \cosec$x - cot x)         
sin2x          $\displaystyle {\textstyle\frac{1}{2}}$x - $\displaystyle {\textstyle\frac{1}{4}}$sin(2x)         
cos2x          $\displaystyle {\textstyle\frac{1}{2}}$x + $\displaystyle {\textstyle\frac{1}{4}}$sin(2x)         
tan2x          tan x - x         

sin(ax)sin(bx)          $\displaystyle {\textstyle\frac{1}{2}}$$\displaystyle \left(\vphantom{\frac{\sin(a-b)x}{a-b} - \frac{\sin(a+b)x}{a+b}
}\right.$$\displaystyle {\frac{\sin(a-b)x}{a-b}}$ - $\displaystyle {\frac{\sin(a+b)x}{a+b}}$$\displaystyle \left.\vphantom{\frac{\sin(a-b)x}{a-b} - \frac{\sin(a+b)x}{a+b}
}\right)$          a$ \ne$±b
sin(ax)cos(bx)          - $\displaystyle {\textstyle\frac{1}{2}}$$\displaystyle \left(\vphantom{\frac{\cos(a-b)x}{a-b} + \frac{\cos(a+b)x}{a+b}
}\right.$$\displaystyle {\frac{\cos(a-b)x}{a-b}}$ + $\displaystyle {\frac{\cos(a+b)x}{a+b}}$$\displaystyle \left.\vphantom{\frac{\cos(a-b)x}{a-b} + \frac{\cos(a+b)x}{a+b}
}\right)$          a$ \ne$±b
cos(ax)cos(bx)          $\displaystyle {\textstyle\frac{1}{2}}$$\displaystyle \left(\vphantom{\frac{\sin(a-b)x}{a-b} + \frac{\sin(a+b)x}{a+b}
}\right.$$\displaystyle {\frac{\sin(a-b)x}{a-b}}$ + $\displaystyle {\frac{\sin(a+b)x}{a+b}}$$\displaystyle \left.\vphantom{\frac{\sin(a-b)x}{a-b} + \frac{\sin(a+b)x}{a+b}
}\right)$          a$ \ne$±b
x sin(ax)          $\displaystyle {\frac{1}{a^2}}$(sin(ax) - ax cos(ax))         
x cos(ax)          $\displaystyle {\frac{1}{a^2}}$(cos(ax) + ax sin(ax))         
arcsin x          x arcsin x + $\displaystyle \sqrt{1-x^2}$         
arccos x          x arccos x - $\displaystyle \sqrt{1-x^2}$         
arctan x          x arctan x - $\displaystyle {\textstyle\frac{1}{2}}$ln(1 + x2)         
eax + b          $\displaystyle {\frac{1}{a}}$eax + b         
xeax          $\displaystyle {\frac{ax-1}{a^2}}$eax         
eaxsin(bx)          $\displaystyle {\frac{e^{ax}}{a^2 +b^2}}$(a sin(bx) - b cos(bx))         
eaxcos(bx)          $\displaystyle {\frac{e^{ax}}{a^2 +b^2}}$(a cos(bx) + b sin(bx))         
sinh x          cosh x         
cosh x          sinh x         
tanh x          lncosh x         
ln x          x ln x - x         
x ln(x)          x2($\displaystyle {\textstyle\frac{1}{2}}$ln x - $\displaystyle {\textstyle\frac{1}{4}}$)         
$\displaystyle {\frac{\ln x}{x}}$          $\displaystyle {\textstyle\frac{1}{2}}$ln2x         
$\displaystyle {\frac{1}{x\ln x}}$          ln(ln(x))         


next up previous contents
Next: Solutions to Exercises Up: Appendices Previous: Appendices   Contents
Ian Craw 2000-01-20