next up previous contents
Next: Questions 2 (Hints and Up: Applications of Integration Previous: Intervals   Contents

Further Properties of the Definite Integral

The `area' interpretation of the definite integral gives us the following extra properties:

    if     f (x)$\displaystyle \ge$0    on     [a, b]    then     $\displaystyle \int_{a}^{b}$f (x) dx$\displaystyle \ge$ 0

(If the graph does not go below the x-axis the integral is not going to be negative.)

    if     f (x)$\displaystyle \ge$g(x)    on     [a, b]    then     $\displaystyle \int_{a}^{b}$f (x) dx$\displaystyle \ge$$\displaystyle \int_{a}^{b}$g(x) dx

(If the graph of f never goes below the graph of g then the area under the f graph is greater than that under the g graph. That explanation makes sense if both graphs are above the x-axis, but the result is true in general as you can see by using the first property on the function h(x) = f (x) - g(x).)

    if     m$\displaystyle \le$f (x)$\displaystyle \le$M    on     [a, b]    then     m(b - a)$\displaystyle \le$$\displaystyle \int_{a}^{b}$f (x) dx$\displaystyle \le$M(b - a)

(Think of m as the constant function g(x) = m and use the earlier results, together with $ \int_{a}^{b}$m dx = m(b - a). Similarly for M.)

Finally, a property that is often quite useful

$\displaystyle \left\vert\vphantom{\int_a^b f(x) dx}\right.$$\displaystyle \int_{a}^{b}$f (x) dx$\displaystyle \left.\vphantom{\int_a^b f(x) dx}\right\vert$$\displaystyle \le$$\displaystyle \int_{a}^{b}$|f (x)| dx


next up previous contents
Next: Questions 2 (Hints and Up: Applications of Integration Previous: Intervals   Contents
Ian Craw 2000-01-20